Metcalfe's law for bitcoin price

Metcalfe's law for bitcoin price

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the square function number of users times the average transaction value. 94% of the bitcoin moved over the past four years is explained by that equation.

It does't make sense for me about a mathematical equation of 94% explained bitcoin price in this article.

If I'd like to predict a bitcoin price of following day using this equation, is this as following?

  square function number of users × the average transaction value

       ↓
  square number of unique addresses per day × (trade volume(USD) per day / number of transactions per day)         

     ↓

604,054^2 × (597,502,689 / 271,995) = 801,644,073,110,452

date: 2017/11/14 00:00

Here's an inline link to [reference unique addresses (http://ift.tt/2ipbe10)

Here's an inline link to [reference trade volume] (http://ift.tt/2AQB2tL)

Here's an inline link to [reference transactions] (http://ift.tt/2ip7Pzr)

Answer is very huge number. Could someone explain that concretely where the wrong is?

Thank you

http://ift.tt/2ANi6vZ

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